Solve \(\frac{1}{3}\)(5 - 3x) < \(\frac{2}{5}\)(3 - 7x)

  • A x > \(\frac{7}{22}\)
  • B x < \(\frac{7}{22}\)
  • C x > \(\frac{-7}{27}\)
  • D x < \(\frac{-7}{27}\)
waec 2020mathematics

The correct answer is D. x < \(\frac{-7}{27}\)

\(\frac{1}{3}\)(5 - 3x) < \(\frac{2}{5}\)(3 - 7x)

5(5 - 3x) < 6(3 - 7x)

25 - 15x < 18 - 42x 

- 15x + 42x < 18 - 25

\(\frac{27x}{27}\) < \(\frac{-7}{27}\)

x < \(\frac{-7}{27}\)

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