Given that x is directly proportional to y and inversely proportional to Z, x = 15 when y = 10 and Z = 4, find the equation connecting x, y and z

  • A x = \(\frac{6y}{z}\)
  • B x = \(\frac{12y}{z}\)
  • C x = \(\frac{3y}{z}\)
  • D x = \(\frac{3y}{2z}\)
waec 2020mathematics

The correct answer is A. x = \(\frac{6y}{z}\)

\(x\) x \(\frac{y}{z}\) 

x = \(\frac{ky}{z}\)

15 = \(\frac{10k}{4}\) 

 \(\frac{60}{10}\) = k = 6

Therefore; x = \(\frac{6y}{z}\)

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