A box contains 12 identical balls of which 5 are red, 4 blue, and the rest are green. If a ball is selected at random from the box, what is the probability that it is green?

  • A \(\frac{3}{4}\)
  • B \(\frac{1}{2}\)
  • C \(\frac{1}{3}\)
  • D \(\frac{1}{4}\)
waec 2020mathematics

The correct answer is D. \(\frac{1}{4}\)

No. of red = 5

No. of blue = 4

No. of green = 3

Total = 12

Pr(Green) = \(\frac{3}{12} = \frac{1}{4}\)

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