If (x + 2) is a factor of x\(^2\) +px - 10, find the value of P.

  • A 3
  • B -3
  • C 7
  • D -7
waec 2020mathematics

The correct answer is B. -3

x + 2 = 0

x -2

x\(^2\) = px - 10 = 0

(-2)\(^2\) - 2p - 10 = 0

4 - 2p - 10 = 0

\(\frac{-2p}{-2} = \frac{6}{-2}\) \(\to\) p = -3

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