In the diagram, O is the centre of the circle. If < NLM = 74\(^o\), < LMN = 39\(^o\) and < LOM = x, find the value of x.

  • A 134\(^o\)
  • B 126\(^o\)
  • C 113\(^o\)
  • D 106\(^o\)
waec 2020mathematics

The correct answer is A. 134\(^o\)

L\(N\)M = 180\(^o\) - (74\(^o\) + 39\(^o\)) 

180\(^o\) - 113\(^o\) 

= 67\(^o\)

L\(^O\)

M = x = 2 x 67\(^o\) 

= 134\(^o\)

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