make u the subject in x =\(\frac{2u-3}{3u + 2}\)

  • A u = \(\frac{2x + 3}{3x - 2}\)
  • B u = \(\frac{2x - 3}{3x - 2}\)
  • C u = \(\frac{2x + 3}{2 - 3x}\)
  • D u = \(\frac{2x + 3}{3x + 2}\)
waec 2021mathematics

The correct answer is C. u = \(\frac{2x + 3}{2 - 3x}\)

x =\(\frac{2u-3}{3u + 2}\)

cross multiply

x(3u + 2) = 2u - 3

3ux + 2x = 2u - 3

collect like terms of u

2x + 3 = 2u - 3ux 

\(\frac{2x + 3}{2 - 3x}\) = u

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