In the diagram O is the centre of the circle PQRS, ∠PQR = 72° and OR is parallel to PS. Find .

  • A 18°
  • B 108°
  • C 54°
  • D 36°

The correct answer is D. 36°

Angle at the centre O is twice the angle at the circumference.

i.e O = 72° * 2 = 144°

∠OPS = 180 - 144 = 36°

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