M varies directly as n and inversely as the square of p. If M= 3 when n = 2 and p = 1, find M in terms of n and p.

  • A \(\frac{3n}{2p^2}\)
  • B \(\frac{2n}{3p^2}\)
  • C \(\frac{2n}{3p}\)
  • D \(\frac{3n^2}{2p^2}\)
waec 2022mathematics

The correct answer is A. \(\frac{3n}{2p^2}\)

M = \(\frac{nk}{p^2}\) 

k →  \(\frac{mp^2}{n}\) =  \(\frac{3x1^2}{2}\)

k =  \(\frac{3}{2}\)

:  m = \(\frac{3xn}{2p^2}\)

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