If a = 3 and b = -7, find the value of \(\frac{5b+(a+b)^2}{(a-b)^2}\)

  • A 0.51
  • B 0.91
  • C -0.19
  • D -0.51

The correct answer is C. -0.19

\(\frac{5b+(a+b)^2}{(a-b)^2}\)

= \(\frac{5 * -7 +(3+ -7)^2}{(3- -7)^2}\)

=  \(\frac{-35 + 16}{10^2}\)

=  \(\frac{-19}{100}\) or -0.19

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