In the diagram, ∠POQ = 150 and the radius of the circle PSQR is 4.2cm. [take π = 22/7]
What is the length of the minor arc?
The correct answer is A. 11cm
\(\frac{θ}{360}\) * 2 * Ï * r â \(\frac{150 * 2 * 22 * 4.2}{360 x 7}\)
= 11cm
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