In the diagram, ∠POQ = 150 and the radius of the circle PSQR is 4.2cm. [take π = 22/7]

What is the length of the minor arc?

  • A 11cm
  • B 15.4cm
  • C 17.64cm
  • D 23.10cm

The correct answer is A. 11cm

\(\frac{θ}{360}\)  * 2 * Ï€ * r → \(\frac{150 * 2 * 22 * 4.2}{360 x 7}\)

= 11cm

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