The lengths of the parallel sides of a trapezium are 9cm and 12cm. If the area of the trapezium is 105cm\(^2\), find the perpendicular distance between the parallel sides.

  • A 5cm
  • B 7cm
  • C 10cm
  • D 15cm

The correct answer is C. 10cm

Area of a trapezium = \(\frac{[a+b]h}{2}\) 

105 = \(\frac{[9+12]h}{2}\) â†’ 105 x 2 =21h

h = \(\frac{210}{21}\) â†’ 10cm

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