Solve 6x\(^2\) = 5x - 1

  • A x = 2,3
  • B x = 0,3
  • C x = \(\frac{1}{2}\), \(\frac{1}{3}\)
  • D x = \(\frac{1}{2}\), \(\frac{-1}{3}\)

The correct answer is C. x = \(\frac{1}{2}\), \(\frac{1}{3}\)

6x\(^2\) = 5x - 1

 â†’ 6x\(^2\) - 5x + 1 = 0

Factorization:

factors are -3x and -2x

6x\(^2\) - 3x  -2x  + 1 = 0

(6x\(^2\) - 3x) (-2x  + 1) = 0

3x(2x-1) -1(2x-1) = 0

(3x-1) (2x-1) = 0

x = \(\frac{1}{2}\), \(\frac{1}{3}\)

Previous question Next question