Given that log\(_3\) 27 = 2x + 1, find the value of x.

  • A 0
  • B 1
  • C 2
  • D 3
waec 2022mathematics

The correct answer is B. 1

Recall that: log\(_3\) 27 â†’ log\(_3\)3\(^3\)

3log\(_3\)3 → 3 * 1

= 3

Then log\(_3\) 27 = 2x + 1

→ 3 = 2x + 1 

3 - 1 = 2x

2 = 2x

1 = x

Previous question Next question