A student told to draw the graph of y = x2 + 4x - 6. He is then told to draw a liner graph on the same axis such that the intersection of the two graphs will give the solutions to the equation x2 + 4x - 7 = 0, What is the equation of the linear graph he needs to draw?

A student told to draw the graph of y = x² + 4x - 6. He is then told to draw a liner graph on the same axis such that the intersection of the two graphs will give the solutions to the equation x² + 4x - 7 = 0, What is the equation of the linear graph he needs to draw?

A x = 1
B x = -1
C y = 1
D y = -1
E x + y = 1

waec 1988 mathematics

The correct answer is C. y = 1

The linear equation will be the difference between the equation.

y=x² + 4x - 6 and x² + 4x - 7 = 0

y=x² + 4x - 6, ( 0 = x² + 4x - 7)

y = -(-1) y = 1

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