What is the probability of having an odd number in a single toss of a fair die?

  • A 1/6
  • B 1/3
  • C 1/2
  • D 2/3
  • E 5/6
waec 1988mathematics

The correct answer is C. 1/2

n(S) = 6(odd) = {1, 3, 5}

n(odd) = 3

pr(odd) = \(\frac{n(odd)}{n(S)}\) 3/6 =1/2

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