In the diagram above, TPS is a straight line, PQRS is a parallelogram with base QR and height 8cm. |QR| = 6cm and the area of triangle QST is 52cm2. Find the area of ΔQPT

  • A 39cm2
  • B 28cm2
  • C 24cm2
  • D 21cm2
  • E 19cm2
waec 1989mathematics

The correct answer is B. 28cm2

Area of \(\Delta\)QST = 52cm\(^2\); height = 8cm

b=base length; but A = 1/2 b x h

=52=1/2 x b x 8cm = 104 =8b

b=104/8 = 13cm; ST= 13cm; PS = 6cm

TP = 13 - 6 = 7cm;

area of \(\Delta\)QST = 1/2 b x h

= 1/2 x 7 x 8/1 = 28cm\(^2\)

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