Points X and Y are respectively 20km North and 9km East of a point O. What is the bearing of Y from X? Correct to the nearest degree
The correct answer is C. 156o
tan\(\theta\) = 9/20 = 0.45
\(\theta\) = tan\(^{-1}\) 0.45 = 24.2°
the bearing of y from x = 180 0 - 0 = 180° - 24.2°
the bearing = 155.8°
\(\approxeq\) 156°
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