In the diagram above O is the center of the circle, if ∠PAQ = 75o, what is the value of ∠PBQ?

  • A 15o
  • B 75o
  • C 105o
  • D 150o
  • E 210o

The correct answer is C. 105o

< PBQ = 180° - 75° (opp angles of a cyclic quadrilateral)

= 105°

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