What is the probability that 3 customers waiting in a bank will be served in the sequence of their arrival at the bank

  • A 1/6
  • B 1/3
  • C 1/2
  • D 2/3
  • E 5/6
waec 1989mathematics

The correct answer is A. 1/6

Probability that 3 customers are attended to in the sequence they arrive 

= prob of attending to the 1st arrival x prob of attending to the second last x prob of attending to the last

= \(\frac{1}{3} \times \frac{1}{2} \times \frac{1}{1}\)

= \(\frac{1}{6}\)

Previous question Next question