Factorize 2e\(^2\) - 3e + 1

  • A (2e-1) (e-1)
  • B (e+1) (2e+1)
  • C (2e+3) (e+2)
  • D (2e-3) (e-1)
  • E (e2-3(2e-1)
waec 1990mathematics

The correct answer is A. (2e-1) (e-1)

2e\(^2\) - 3e + 1

2e\(^2\) - 2e - e + 1

2e(e - 1) - 1(e - 1)

(2e - 1)(e - 1)

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