In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR

  • A 5.12cm2
  • B 9.60cm2
  • C 10.24cm2
  • D 20.48cm2
  • E 40.96cm2
waec 1990mathematics

The correct answer is C. 10.24cm2

Area of a triangle = \(\frac{1}{2} \times b \times h\)

Area of \(\Delta\) SQR = \(\frac{1}{2} \times 6.4 \times 3.2\)

= 10.24 cm\(^2\)

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