Simplify: log6 + log2 - log12

  • A -4
  • B -1
  • C 0
  • D 1
  • E 4
waec 1991mathematics

The correct answer is C. 0

log 6 + log 2 - log 12

= \(\log (\frac{6 \times 2}{12})\)

= \(\log 1\)

= 0

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