In the diagram above, ATR is a tangent at the point T to the circle center O, if ∠TOB = 145°, find ∠TAO

  • A 20o
  • B 35o
  • C 45o
  • D 55o
  • E 65o
waec 1991mathematics

The correct answer is D. 55o

From the figure, < ATO = 90°

< AOT = 180° - 145° = 35°

\(\therefore\) < TAO = 180° - (90° + 35°)

= 55° (sum of angle in a triangle)

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