If events X and Y are mutually exclusive, . P(X) = 1/3 and P(Y) = 2/5, P(X∩Y) is

  • A o
  • B 2/15
  • C 11/15
  • D 4/15
  • E 1
waec 1991mathematics

The correct answer is B. 2/15

P(X \(\cap\) Y) = \(\frac{1}{3} \times \frac{2}{5}\)

= \(\frac{2}{15}\)

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