Evaluate \(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)

  • A 0.2
  • B 2
  • C 100
  • D 409
  • E 490
waec 1992mathematics

The correct answer is B. 2

\(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)

= \(\log_{10} (\frac{25 \times 32}{8})\)

= \(\log_{10} 100 \)

= 2

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