The nth term of a sequence is given by 3.2\(^{n-2}\). Write down the first three terms of the sequence.

  • A 2/3, 0, 6
  • B 3/2, 3, 6,
  • C 2/3, 3, 8/3
  • D 2/3, 3/4, 6
  • E 2/3, 3, 1/3
waec 1992mathematics

The correct answer is B. 3/2, 3, 6,

\(T_n = 3. 2^{n - 2} \\

T_{1} = 3. 2^{1 - 2} = 3. 2^{-1} \\

T_1 = \frac{3}{2} \)

\(T_2 = 3. 2^{2 - 2} \\

T_2 = 3. 2^0  = 3\)

\(T_3 = 3. 2^{3 - 2} = 3. 2^1 \\

T_3 = 6\)

The first 3 terms of the sequence are \(\frac{3}{2}\), 3 and 6.

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