Write as a single fraction \(\frac{1}{1 - x} + \frac{2}{1 + x}\)

  • A \(\frac{x + 3}{1 - x^2}\)
  • B \(\frac{3 - x}{(1 - x)^2}\)
  • C \(\frac{3 - x}{1 + x^2}\)
  • D \(\frac{3 - x}{(1 + x)^2}\)
  • E \(\frac{3 - x}{1 - x^2}\)
waec 1992mathematics

The correct answer is E. \(\frac{3 - x}{1 - x^2}\)

\(\frac{1}{1 - x} + \frac{2}{1 + x}\)

= \(\frac{(1 + x) + 2(1 - x)}{(1 - x)(1 + x)}\)

= \(\frac{1 + x + 2 - 2x}{1 - x^2}\)

= \(\frac{3 - x}{1 - x^2}\)

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