In the diagram above PQT is a tangent to the circle QRS at Q. Angle QTR = 48° and ∠QRT = 95°. Find ∠QRT

  • A 48o
  • B 45o
  • C 37o
  • D 32o
  • E 30o
waec 1992mathematics

The correct answer is C. 37o

∠RQT = 180° - (95° + 48°) = 73°

∠OQR = 90° - 37° = 53°

∠QOR = 180° - (53° + 53°) = 74°

QSR = 74°/2 = 37°

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