The nth term of a sequence is given by (-1)\(^{n-2}\) x 2\(^{n-1}\). Find the sum of the second and third terms.

  • A -2
  • B 1
  • C 2
  • D 6
  • E 12

The correct answer is A. -2

when n = 2

(-1)\(^{n-2}\) 2\(^{n+1}\) = 2

When n = 3

(-1)\(^{n-2}\) 2\(^{n+1}\) = -4

Sum = 2 - 4 = -2

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