Question

In the diagram above, |PQ| = |QR|, |PS| = |RS|, ∠PSR = 30^o and ∠PQR = 80^o. Find ∠SPQ.

Answer 1

The correct answer is B. 25^o

Join PR

QRP = QPR

= 180 - 80 = ¹⁰⁰/₂₀ = 50^o

SRP = SPR

= 180 - 30 = ¹⁵⁰/₂ = 75^o

â´ SPQ = SPR - QPR

= 75 - 50 = 25^o