Given that m = -3 and n = 2 find the value of \(\frac{3n^2 - 2m^3}{m}\)

  • A -22
  • B -14
  • C 14
  • D 22

The correct answer is A. -22

Given that m = -3, n = 2, the value of

\(\frac{3n^2 - 2n^3}{m}\\

\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)

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