From the diagram above. ABC is a triangle inscribed in a circle center O. ∠ACB = 40o and |AB| = x cm. calculate the radius of the circle.

  • A \(\frac{x}{sin 40^o}\)
  • B \(\frac{x}{cos 40^o}\)
  • C \(\frac{x}{2 sin 40^o}\)
  • D \(\frac{x}{2 cos 40^o}\)
waec 1999mathematics

The correct answer is C. \(\frac{x}{2 sin 40^o}\)

No explanation given
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