In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y

  • A x
  • B \(\frac{x^2}{y}\)
  • C \(\frac{y}{x^2}\)
  • D \(\frac{y^2}{x}\)
waec 1999mathematics

The correct answer is D. \(\frac{y^2}{x}\)

\(\frac{x}{x+y}=\frac{y}{x+CE}\\

xy + xCE = xy + y^2\\

∴xCE = y^2\\

CE=\frac{y^2}{x}\)

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