Make x the subject of the relation d = \(\sqrt{\frac{6}{x} - \frac{y}{2}}\)

  • A x = \(\frac{6 + 12}{d^2 + y}\)
  • B x = \(\frac{12}{d^2 - y}\)
  • C x = \(\frac{12}{y} - 2d^2\)
  • D x = \(\frac{12}{2d^2 + y}\)

The correct answer is D. x = \(\frac{12}{2d^2 + y}\)

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