0.5kg of water at 10oC is completely converted to ice by extracting 188000J of heat from it. If the specific heat capacity of water is 4200J kg-1C-1, calculate the specific latent heat of fusion of ice.

  • A 9.0 KJ kg-1
  • B 84.0 KJ kg-1
  • C 168.0 KJ kg-1
  • D 334.0 KJ kg-1
  • E 336.0 KJ kg-1

The correct answer is D. 334.0 KJ kg-1

Q = mcΔθ = (0.5 x 4200 x 10) + 0.5L

L = 334000

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