All the heat generated by a current of 2A passing through a resistor of 6Ω for 2.5s is used to evaporate 5 g of a liquid at its boiling point. What is the specific latent heat of the liquid?
The correct answer is B. 120 Jg-1
Electrical Energy = Heat Energy.
I2Rt = ml
22 x 6 25 = 5 x L.
L = 120 Jg-1.
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