An object R leaves a platform XY with a horizontal velocity of 7m-1 and lands at Q. lf it takes the same object 0.3s to fall freely from Y to P, calculate the distance PQ.(Take g = 1Oms2)

  • A 7.30m
  • B 2.55m
  • C 2.10m
  • D 1.65m
  • E 0.45m.

The correct answer is C. 2.10m

D = v x t = 7 x 0.3 = 2.1m

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