A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.

A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.

A 0.15 A
B 0.20 A
C 0.60A
D 3.00A
E 6.67 A.

waec 1990 physics

The correct answer is A. 0.15 A

I = E/R + r = 1.5/2.5 + 0.5 + 7 = 0.15

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