A metal of mass 1.5 kg was heated from 27oC to 47oC in 4 minutes by a boiling ring of 75 W rating. Calculate the specific heat capacity of the metal, (Neglect heat losses to the surrounding)
The correct answer is B. 6.0 X102J kg-10C-1
I.Vt = mcθ; C = I.Vt/mθ = 75 x 4 x 60/1.5 x 20
= 6.0 X102J kg-10C-1
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