A particle of charge 5C moves perpendicularly to a magnetic Held of magnitude C.01 T. If the velocity of the charge is 1.5ms'2, calculate the magnitude of the force exerted on the particle

A particle of charge 5C moves perpendicularly to a magnetic Held of magnitude C.01 T. If the velocity of the charge is 1.5ms'2, calculate the magnitude of the force exerted on the particle

A 0.050 N
B 0.075N
C 0.0300N
D 3.300N
E 0.000N

waec 1993 physics

The correct answer is B. 0.075N

F = eV = 0.01 x 5 x 1.5 = 0.075N

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