If the current in the resistor R in diagram above is 0.05A, calculate the p.d. across the inductor.

  • A 2.5V
  • B 25.0V
  • C 49.0V
  • D 50.0V
  • E 250.0V
waec 1995physics

The correct answer is A. 2.5V

V= i × \(_l\)

X\(_l\) = inductive reactance â†’ 50

I = current → 0.05A

V = 0.05 × 50

V = 2.5volt

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