Two simple pendula x and y make 400 and 500 oscillations respectively in equal time. If the period of oscillation of x is 1.5 seconds, what is the period of oscillation of y?

  • A 0.53s
  • B 0.83s
  • C 1.20s
  • D 1.50s
  • E 1.88s.

The correct answer is C. 1.20s

where f = \(\frac{oscillations}{time}\)

period = 1/ f or \(\frac{time}{oscillations}\)

For pendulum x:

where period = 1.5 and oscillation = 400

time = oscillations X 1.5 = 600s

For pendulum y:

\(\frac{time}{oscillations}\) â†’ 600/500

period for y = 1.2s

period =

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