Calculate the amount of heat generated in an external load of resistance 8Ω if an alternating current of peak value 5A is passed through for 100s.

  • A 20,000J
  • B 10,000J
  • C 5,000J
  • D 4,000J
  • E 200J

The correct answer is A. 20,000J

E=I\(^2\)rt

E=5\(^2\) * 8 * 100

E=20000j

Heat Energy Generated(Q) ⇔ Energy(E)

Q = 20000j

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