In a series R-L-C circuit, R = 10\(\Omega\), \(X_{c}\)= 4\(\Omega\) and \(X_{L}\) = 9\(\Omega\). The impedance of the circuit is

  • A 4.1\(\Omega\)
  • B 5.0\(\Omega\)
  • C 10.8\(\Omega\)
  • D 11.2\(\Omega\)
waec 2018physics

The correct answer is D. 11.2\(\Omega\)

The impedance for a RLC circuit is

\(Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}\)

= \(\sqrt{10^{2} + (9 - 4)^{2}}\)

= \(\sqrt{125}\)

= 11.18\(\Omega\) \(\approxeq\) 11.2\(\Omega\)

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