A nuclide is represented by \(_{32}^{70}B\). Determine its neutron-proton ratio

  • A 0.5
  • B 0.8
  • C 1.2
  • D 1.5

The correct answer is C. 1.2

The element B has a mass number of 70 with atomic number 32. Hence, B has 32 protons and (70-32) = 38 neutrons.

The neutron- proton ratio is 38:32 = \(\frac{38}{32} = 1.1875\)

\(\approxeq 1.2\)

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