The angle at which a projectile must be fired to cover maximum range is

  • A 30°
  • B 45°
  • C 60°
  • D 90°

The correct answer is B. 45°

The formula is \(\frac{v^{2}sin2\theta}{g}\) 

And the sine graph is highest at 1 with its inverse as 90°. Hence, \(2\theta\) = 90°

\(\theta\) = 45°

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