A motorist travelling at 72\(kmh^{-1}\) had his eyes shut for 0.4s during a hard sneeze. Calculate the distance covered by him during this time interval.

  • A 50.0m
  • B 28.8m
  • C 18.0m
  • D 8.0m
waec 2017physics

The correct answer is D. 8.0m

Convert velocity from \(kmh^{-1}\) to \(ms^{-1}\), by multiplying \(\frac{1000}{3600}\), 

\(72 \times \frac{1000}{3600}\) = \(20ms^{-1}\)

Therefore, distance covered in 0.4s =  \(20 \times 0.4 = 8m\)

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