A plane is inclined at an angle \(\theta\) to the horizontal. Its velocity ratio is

  • A \(sin\theta\)
  • B \(tan\theta\)
  • C \(\frac{1}{sin\theta}\)
  • D \(\frac{1}{tan\theta}\)
waec 2017physics

The correct answer is C. \(\frac{1}{sin\theta}\)

Velocity ratio = \(\frac{Effort distance}{Load distance}\)

On an inclined plane, it is the inverse of \(sin\theta\) = \(\frac{1}{sin\theta}\)

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