The diagram above illustrates a wave setup between two fixed ends 4.0m apart. If the speed of the wave is 1.0\(ms^{-1}\), its wavelength and frequency respectively are

  • A 1m; 0.25Hz
  • B 2m; 0.25Hz
  • C 2m; 0.50Hz
  • D 4m; 0.50Hz

The correct answer is C. 2m; 0.50Hz

For the 4th harmonic, \(L = 2\lambda\)

\(4m = 2\lambda \implies \lambda = \frac{4m}{2}\)

=\(2m\)

Recall, \(v = f\lambda\)

\(1 = f \times 2 \implies f = \frac{1}{2}\)

= 0.50Hz

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