<table border=\"1\" cellpadding=\"1\" cellspacing=\"1\" style=\"width:500px\"><tr><td>n = \(\alpha\)</td><td>0.06eV</td></tr><tr><td>E=3</td><td>-1.6eV</td></tr><tr><td>E=2</td><td>-3.7eV</td></tr><tr><td>E=1</td><td>-5.5eV</td></tr><tr><td>E=0</td><td>-10.4eV</td></tr></table>The energy levels in the mercury atom is illustrated in the table above. Calculate the ionisation energy of the atom.

n = \(\alpha\) 0.06eV E=3 -1.6eV E=2 -3.7eV E=1 -5.5eV E=0 -10.4eV The energy levels in the mercury atom is illustrated in the table above. Calculate the ionisation energy of the atom.

The energy levels in the mercury atom is illustrated in the table above. Calculate the ionisation energy of the atom.

The correct answer is B. +10.4eV

No explanation given